5x-0.15x^2=0

Solution for 5x-0.15x^2=0 equation:

5x-0.15x^2=0

a = -0.15; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-0.15)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-0.15}=\frac{-10}{-0.3}
=33+0.1/0.3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-0.15}=\frac{0}{-0.3}
=0
$